標題:
Thermodynamics Question
發問:
How to calculate this question 170ml of water at 295K is mixed with 90ml of water at 355K. What is the Final temperature. THX
最佳解答:
Let T be the final temperature. Heat absorbed by 170 mL (= 170 g) of water = 170 x 4.2 x (T - 295) where 4.2 J/g-K is the specific heat capacity of water Heat released by 90 mL(=90 g) of water = 90 x 4.2 x (355 - T) Assume no heat lost to the surroundings heat loss = heat gain 90 x 4.2 x (355 - T) = 170 x 4.2 x (T - 295) solve for T gives T = 316 K The final tempeature is 316 K
Thermodynamics Question
發問:
How to calculate this question 170ml of water at 295K is mixed with 90ml of water at 355K. What is the Final temperature. THX
最佳解答:
Let T be the final temperature. Heat absorbed by 170 mL (= 170 g) of water = 170 x 4.2 x (T - 295) where 4.2 J/g-K is the specific heat capacity of water Heat released by 90 mL(=90 g) of water = 90 x 4.2 x (355 - T) Assume no heat lost to the surroundings heat loss = heat gain 90 x 4.2 x (355 - T) = 170 x 4.2 x (T - 295) solve for T gives T = 316 K The final tempeature is 316 K
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