標題:

(急)這一條因式分解如何計算?

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發問:

x^3-y^3+x-y點解等於(x-y)(x^2+xy+y^2+1) ??

最佳解答:

x^3-y^3+x-y =x^3-y^3+ (x-y) =x^3+x^2y+xy^2-y^3-xy^2-x^2y +(x-y) =x(x^2+xy+y^2)-y(x^2+xy+y^2) +(x-y) =(x-y)(x^2+xy+y^2)+(x-y) =(x-y)(x^2+xy+y^2+1)

其他解答:

X^3 - Y^3 + X - Y = (X - Y)(X^2 +XY +Y^2 +1)? (X - Y)(X^2 +XY +Y^2 +1) = X^3 + X^2Y + XY^2 + X - X^2Y - XY^2 - Y^3 -Y = X^3 - Y^3 + X - Y
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