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標題:
factorization F.3
發問:
最佳解答:
1a) 8x3 – 27 = (2x)3 – 33 = (2x – 3)[(2x)2 + (2x)(3) + (3)2] = (2x – 3)(4x2 + 6x + 9) 1b) 16x3 – 4x – 48 = 2(8x3 – 2x – 24) = 2(8x3 – 27 – 2x + 3) = 2[(2x – 3)(4x2 + 6x + 9) – (2x – 3)] = 2(2x – 3)(4x2 + 6x + 8) = 4(2x – 3)(2x2 + 3x + 4)
其他解答:
factorization F.3
發問:
此文章來自奇摩知識+如有不便請留言告知
1a) Factorize 8x^3 - 27. 1b) Hence factorize 16x^3 - 4x - 48.最佳解答:
1a) 8x3 – 27 = (2x)3 – 33 = (2x – 3)[(2x)2 + (2x)(3) + (3)2] = (2x – 3)(4x2 + 6x + 9) 1b) 16x3 – 4x – 48 = 2(8x3 – 2x – 24) = 2(8x3 – 27 – 2x + 3) = 2[(2x – 3)(4x2 + 6x + 9) – (2x – 3)] = 2(2x – 3)(4x2 + 6x + 8) = 4(2x – 3)(2x2 + 3x + 4)
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